A block of metal weighing 2 $k g$ is resting on africtionless plane. It is struck by a jet releasing waterat a rate of 1 $k g / s$ with a speed of 5 $m / s$ . Theinitial acceleration of the block will be :-

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Solution

$F = \frac{Δ ρ}{Δ t} = \frac{1 \times 5}{1} = 5 N$
Now $F$ will accelerate block
$F = m a \Rightarrow 5 = 2 \times a \Rightarrow a = 2.5 m / s^{2}$

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A block of metal weighing 2 Kg is resting on a frictionless plane. It is struck by a jet releasing water at a rate of 1 $k g s^{- 1}$ and at a speed of 5 $m s^{- 1}$ . The initial acceleration of the block is

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A block of metal weighing 2 kg is resting on africtionless plane. It is struck by a jet releasing waterat a rate of 1 kg/s with a speed of 5 m/s . Theinitial acceleration of the block will be :-

F=ΔρΔt=1×51=5NNow F will accelerate blockF=ma⇒5=2×a⇒a=2.5m/s2

A block of metal weighing 2 $k g$ is resting on africtionless plane. It is struck by a jet releasing waterat a rate of 1 $k g / s$ with a speed of 5 $m / s$ . Theinitial acceleration of the block will be :-

$F = \frac{Δ ρ}{Δ t} = \frac{1 \times 5}{1} = 5 N$
Now $F$ will accelerate block
$F = m a \Rightarrow 5 = 2 \times a \Rightarrow a = 2.5 m / s^{2}$