This is a rectangular block, also called a cuboid.
It has 3 different faces, with different areas.
Force = 30N.
We know,
Pressure = Force/Area.
When force is constant, pressure ∞ 1/Area.
Therefore, pressure is maximum when area is minimum and vice versa.
By calculating the area of three faces, we get,
⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻²...