A block of unknown mass it at rest on a rough horizontal surface. A force F is applied to the block. The graph in the figure shows the acceleration of the block with respect to the applied force.
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Solution
Diagram
Acceleration of block, a=F−μmgm⇒a=(1m)F−μg
From the graph;
slope=1m=12⇒m=2kg
and y- intercept: −μg=−2⇒μ=0.2