A block of volume V and of density $σ_{b}$ is placed in liquid of destiny $σ_{1} (σ_{1} > σ_{b})$ , then block is moved upward upto a height h and it is still in liquid $.$ The increase in gravitational Potential energy of the block is $:$

σ_{b} v g h

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(σ_{b} + σ_{1}) V g h

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(σ_{b} - σ_{1}) V g h

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none of these

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Solution

The correct option is A $σ_{b} v g h$
mass of block $(m) = v o l u m e \times d e n s i t y = V \times S_{b}$
$\Rightarrow$ $m = S_{b} V$
Since, we know that gravitational potential energy of block at height $h$
$= m g h$
So, the gravitational potential energy of the block $= S_{b} V_{g} h$

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