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Question

A block of weight 100 N is slowly moved up a smooth incline of inclination 37° by a person. Calculate the work done by the person in moving the block through a distance of 2 m, if the driving force is (a) parallel to the incline and (b) in the horizontal direction.

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Solution

Given:
Weight, mg=100 Nθ=37° and s=2 mForce, F=mg sin 37°=100×35=60 N
So, work done when the force is parallel to incline,
W=FS cos θ=60×2×cos 0° =120 J




In ΔABC, AB=2 mAC=h=s×sin 37°=2.0×sin 37°=1.2 m

∴ Work done when the force is in horizontal direction,

W'=mgh=100×1.2=120 J

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