Question

A block of weight 100 N is lying on a rough horizontal surface .it's coefficient of friction is $\frac{1}{\sqrt{3}}$ the least possible force that can move the block is?

Answer 1

Given,

Weight of the block = 100 N

Coefficient of the friction = $\frac{1}{\sqrt{3}}$

If the weight of the block is 100 N then the force of reaction will also be 100 N

We know,

The frictional force is given as

$f=\mu N$

Putting all the values

$f=\frac{1}{\sqrt{3}}\times 100=\frac{100}{\sqrt{3}}$ N

So minimum force which is required to move the block should be equal to the limiting friction.

So minimum force required = $\frac{100}{\sqrt{3}}$ N