a block of weight 1N rests on an inclined plane of inclination theta with the horizontal. the coefficient of friction between the block and the inclined plane is mu. the minimum force that has to be applied parallel to the inclined plane to make body just move up the plane is

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Solution

$W e i g h t o f t h e o b j e c t a l o n g t h e i n c l i n e d p l a n e = W \sin θ W = 1 N w h e n b l o c k m o v e s u p w a r d, f r i c t i o n w i l l b e i n t h e d o w n w a r d d i r e c t i o n f r = μ R R = n o r m a l r e a c t i o n = W \cos θ f r = μ \cos θ n e t u p w a r d f o r c e = n e t d o w n w a r d f o r e c a p p l i e d f o r c e i n u p w a r d d i r e c t i o n = \sin θ + μ \cos θ$

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a block of weight 1N rests on an inclined plane of inclination theta with the horizontal. the coefficient of friction between the block and the inclined plane is mu. the minimum force that has to be applied parallel to the inclined plane to make body just move up the plane is

Weight ofthe object along the inclined plane =WsinθW = 1Nwhen block moves upward, friction will be in the downward direction fr =μRR = normal reaction = Wcosθfr = μcosθnet upward force = net downward forecapplied force in upward direction = sinθ+μcosθ