CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of weight 200 N is pulled along a rough horizontal surface at a constant speed by a force of 100 N acting at an angle of 30 above the horizontal. The coefficient of friction between the block and the surface is


A

0.43

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.58

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

0.75

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0.85

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

0.58


Since the block moves with a constant velocity, no net force acts on it. Therefore, the horizontal component F cos θ of force F must balance the frictional force force, i.e., fr=F cos θ.

Now, N+F sinθ=mgN=mgF sinθ
Also, fr=μN=μ(mgF sin θ)F cosθ=μ(mgF sin θ)μ=F cosθmgF sin θ=100×32200100×12=13=0.58
Hence, the correct choice is (b).


flag
Suggest Corrections
thumbs-up
46
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon