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Work Energy Theorem Application

A block of we...

Question

A block of weight $50 N$ is pulled $10$ meters across a level floor by the force of $40 N$ directed at $30^{o}$ from the horizontal. $(sin 30^{o} = 0.50, cos 30^{o} = 0.87)$
Find out the normal force between the floor and the block while the block is being pulled ?

50 N

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44 N

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30 N

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25 N

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5 N

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Solution

The correct option is C $30 N$
Given : $F = 40$ N $W = 50$ N
From figure, $F^{'} = F$ $s i n 30^{o} = 40 \times 0.5 = 20$ N
$∴$ Normal force $N = W - F^{'} = 50 - 20 = 30$ N

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A block of weight 50N is pulled 10 meters across a level floor by the force of 40N directed at 30o from the horizontal. (sin30o=0.50,cos30o=0.87)Find out the normal force between the floor and the block while the block is being pulled ?

The correct option is C 30NGiven : F=40 N W=50 NFrom figure, F′=F sin30o=40×0.5=20 N∴ Normal force N=W−F′=50−20=30 N

A block of weight $50 N$ is pulled $10$ meters across a level floor by the force of $40 N$ directed at $30^{o}$ from the horizontal. $(sin 30^{o} = 0.50, cos 30^{o} = 0.87)$
Find out the normal force between the floor and the block while the block is being pulled ?

The correct option is C $30 N$
Given : $F = 40$ N $W = 50$ N
From figure, $F^{'} = F$ $s i n 30^{o} = 40 \times 0.5 = 20$ N
$∴$ Normal force $N = W - F^{'} = 50 - 20 = 30$ N