Question

A block of weight W is pulled on a horizontal surface with a force making angle of theeta with the horizontal. If the angle of friction is alpha then the minimum force required to slide the block is

Answer 1

Dear Student,
$$\begin{gathered} letrequaredminimumforceisF \\ here\mu =\tan \left(\alpha \right) \\ normalforceoblock=W-F\sin \left(\theta \right) \\ forequilibriumF\cos \left(\theta \right)=\mu (W-F\sin (\theta \left)\right) \\ soF=\frac{\tan \left(\alpha \right)W}{\cos \left(\theta \right)+\tan \left(\alpha \right)\sin \left(\theta \right)}=\frac{W\sin \left(\alpha \right)}{\cos (\alpha -\theta )} \\ soformotionofblockF>\frac{W\sin \left(\alpha \right)}{\cos (\alpha -\theta )} \end{gathered}$$
Regard