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Question
A block of weight W is suspended from a spring balance. The lower surface of the block rests on a weighing machine. The spring balance reads W1 and the weighing machine reads W2 (W,W1,W2 are in the same unit). Then :
A block of weight W is suspended from a spring balance. The lower surface of the block rests on a weighing machine. The spring balance reads W1 and the weighing machine reads W2 (W,W1,W2 are in the same unit). Then :
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Solution
The correct options are
A W=W1+W2 if the system is at rest
B W>W1+W2 if the system moves down with some acceleration
D no relation between W1 and W2 can be obtained with the given description of the system
The system will remain rest if W=W1+W2
As we know that acceleration will come due to the force .
The system moves down if W>W1+W2.
Here the readings of the spring balance and the weighing machine are equal to the forces exerted by them on the body.
A W=W1+W2 if the system is at rest
B W>W1+W2 if the system moves down with some acceleration
D no relation between W1 and W2 can be obtained with the given description of the system
The system will remain rest if W=W1+W2
As we know that acceleration will come due to the force .
The system moves down if W>W1+W2.
Here the readings of the spring balance and the weighing machine are equal to the forces exerted by them on the body.
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