Question

A block of wood floats in water with $3/5^{th}$ of its volume inside its surface. Calculate the density of wood. (Take density of water as $1000kg/m^3$)

Answer 1

Step 1: Given data,
Let the total volume of the wooden block = $v{m}^3$
So, the volume of wood immersed in water = $\frac{3}{5}v{m}^3$
The density of water= $1000kg/m^3$

Step 2: Finding the density of the wooden block,
$$\begin{gathered} Weknowthat,\frac{densityofthewoodenblock}{densityofwater}=\frac{volumeofthewoodenblockimmersed}{totalvolumeofthewoodenblock} \\ So,densityofthewoodenblock=\frac{densityofwater\times volumeofthewoodenblockimmersed}{totalvolumeofthewoodenblock}=\frac{1000kg/m^3\times \frac{3}{5}v{m}^3}{v{m}^3}=600kg/m^3 \end{gathered}$$

Hence, the density of wood is $600kg/m^3$.