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Question

A block of wood floats in water with two-thirds of its volume submerged. Its relative density is equal to

A

\frac{1}{3}

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B

\frac{2}{3}

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C

\frac{4}{3}

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D

\frac{1}{9}

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Solution

The correct option is B $\frac{2}{3}$
relative density= density of the part submerged in water/ density of water
Therefore,relative density=2/3

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