A block of wood of density 0-8 -3 has a volume of 60 -3 - The mass of block will be

Given, As formula of density is, Density (d)=mass (m)Volume (V) 0.8 gcm^ 3=mass (m)60cm^3 mass(m) = 0.8 gcm^−3× 60 𝑐𝑚^3 = 48 𝑔 Hence option (c) is correct. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Relative Density

A block of wo...

Question

A block of wood of density $0.8 g c m^{- 3}$ has a volume of $60 c m^{3}$ . The mass of block will be

60.8 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.013 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

48 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $48 g$
Given,
As formula of density is,
$Density (d) = \frac{mass (m)}{Volume (V)}$
$0.8 g c m^{- 3} = \frac{mass (m)}{60 c m^{3}}$

$mass(m) = 0.8 g c m^{- 3} \times 60 c m^{3} = 48 g$

Hence option (c) is correct.

Suggest Corrections

Similar questions

Q. A cork has a volume

25 c m^{3}

. The density of cork is

0.25 g c m^{- 3}

. Find the mass of cork.

Q. A block of wood floats in a liquid of density

0.8 g c m^{- 3}

with one fourth of its volume submerged. In oil the block floats with

60

% of its volume submerged. Find the density of (a) wood and (b) oil

Q. A block of iron has dimensions

2 m \times 0.5 m \times 0.25 m

. The density of iron is

7.8 g c m^{- 3}

. Find the mass of block.

Q. Define relative density. A cylindrical block of wood of height 4.2m and mass 100Kg floats vertically in water. The relative density of wood is 0.8. What height of the block will be seen above the water?
[3 MARKS]

A cylindrical block of wood of height 4.2m and mass 100Kg floats vertically in water. The relative density of wood is 0.8 . What height of the block will be seen above the water ?

Join BYJU'S Learning Program

Explore more

Relative Density

Standard IX Physics

Join BYJU'S Learning Program

A block of wood of density 0.8 gcm−3 has a volume of 60 cm3 . The mass of block will be

The correct option is D 48 g Given, As formula of density is, Density (d)=mass (m)Volume (V) 0.8 gcm−3=mass (m)60cm3 mass(m)=0.8 gcm−3×60 cm3=48 g Hence option (c) is correct.

A block of wood of density $0.8 g c m^{- 3}$ has a volume of $60 c m^{3}$ . The mass of block will be

The correct option is D $48 g$
Given,
As formula of density is,
$Density (d) = \frac{mass (m)}{Volume (V)}$
$0.8 g c m^{- 3} = \frac{mass (m)}{60 c m^{3}}$

$mass(m) = 0.8 g c m^{- 3} \times 60 c m^{3} = 48 g$

Hence option (c) is correct.