Question

A block of wood of mass $24$ kg floats on water. The volume of wood is $0.032$ $m^3$. Find the volume of block below the surface of water. (Density of water $=1000$ kg $m^{-3}$)

Answer 1

Now the density of the wood given by

$\frac{m}{v}=\frac{24}{0.032}$

$=750\frac{kg}{m^3}$

By principle of floation

Mass of wood$=$mass of liquid displaced.

mass of liquid displaced$=24kg$

Volume of liquid displaced (v)

$=\frac{m}{v}=\frac{24}{1000}=0.024m^3$

Therefore, volume of wood inside the water will be

$=\frac{0.024}{0.032}=0.75m^3$