Question

A block reaches the foot of a smooth inclined plane by slipping down with speed $V$. Now, if a disc of same mass as the block is released from same height, then its speed when it reaches the foot of the same plane will be

• A. $\frac{2V}{3}$
• B. $V$
• C. $\frac{V}{2}$
• D. $\frac{V}{\sqrt{2}}$

Answer 1

The correct option is B $V$

Disc will not roll since there is no friction. So, it will follow translatory motion and loss in PE = gain in KE