Question

A block slides down a fixed inclined plane inclination ${37}^o$ with constant speed. If the inclination is changed to ${53}^0$, the acceleration of the block will be $(takeg=10m{s}^{-2},sin{37}^o=3/5)$

• A. $2m{s}^{-2}$
• B. $3.5m{s}^{-2}$
• C. $7m{s}^{-2}$
• D. $6m{s}^{-2}$

Answer 1

The correct option is A $2m{s}^{-2}$

If block is sliding at constant velocity it means that there is some force acting opposite to component of gravity along incline, which is creating negative acceleration.

Negative acceleration = gsin${\theta }_i$=6m/s${}^2$

Thus when angle is changed net acceleration of block = g$sin{\theta }_f$-6=2m/s${}^2$