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Question

A block slides down a slope of angle θ with constant velocity. It is then projected up with a velocity of 10ms1, g=10ms2 and q=30o. The maximum distance it can go up the plane before coming to stop is

A
10m
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B
5m
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C
4m
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D
15m
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Solution

The correct option is B 10m
From above figure
for constant velocity
mg sin30=μ mg cos30

μ=13

when it is thrown upward
a=g sin30+μ g cos30
=10M§2
so in upward journey
u = 10m/s a=m/s2 v=0 s = ?
v2=u2+2as
0=1002(10)s
s=10m

Hence (A) option is correct

965233_1030450_ans_7cbdf08eb2f947299e01c56626ac4239.jpeg

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