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Standard XII

Physics

Newton's Second Law: Rotatory Version

A block tied ...

Question

A block tied between two identical springs is in equilibrium. If upper spring is cut, then the acceleration of the block just after the cut is $5 m s^{- 2}$ . Now if instead of upper string, the lower spring is cut, then the acceleration of the block just after the cut will be (Take $g = 10 m / s^{2})$ :

1.25 m s^{- 2}

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5 m s^{- 2}

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10 m s^{- 2}

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2.5 m s^{- 2}

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Solution

The correct option is B $5 m s^{- 2}$
Just after the cut, the initial speed is provided by the spring force only, be it the upper one or the lower one.
Force on the block on either side is same, that is $k x$ ; hence the acceleration just after the cut would also be same that is $5 m / s^{2}$ .
$a = \frac{k x}{m}$
Option B.

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A block tied between two identical springs is in equilibrium. If upper spring is cut, then the acceleration of the block just after the cut is 5 ms−2. Now if instead of upper string, the lower spring is cut, then the acceleration of the block just after the cut will be (Take g=10 m/s2):

The correct option is B 5 ms−2Just after the cut, the initial speed is provided by the spring force only, be it the upper one or the lower one.Force on the block on either side is same, that is kx; hence the acceleration just after the cut would also be same that is 5m/s2.a=kxmOption B.