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Question

# A block weighing 10kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. If a force acts down at 600 from the horizontal, how large can it be without causing the block to move? (g=10ms−2)

A
346N
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B
446N
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C
746N
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D
846N
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Solution

## The correct option is A 746NNormal force is given by N=mg+Fsinθ=100+F√32Thus maximum static friction, fS,max=μN=0.5(100+F√32)=50+F√34This friction force is equal to the horizontal component of applied force at the time motion starts.Thus, 50+F√34=Fcos600=F2 F(12−√34)=50F=500.067≈746 N

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