A boat crossing a river moves with a velocity v relative to still water. The river is flowing with a velocity $\frac{v}{2}$ with respect to the bank. The angle with respect to the flow direction with which the boat should move to minimize the drift is:

30^{\circ}

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60^{\circ}

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150^{\circ}

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120^{\circ}

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Solution

The correct option is D $120^{\circ}$

$θ = s i n^{- 1} (\frac{\frac{v}{2}}{v})$
$θ = 30^{\circ}$
So angle with direction of flow of river is $90^{\circ} + 30^{\circ} = 120^{\circ}$

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A boat crossing a river moves with a velocity v relative to still water. The river is flowing with a velocity v2 with respect to the bank. The angle with respect to the flow direction with which the boat should move to minimize the drift is:

The correct option is D 120∘ θ=sin−1(v2v) θ=30∘ So angle with direction of flow of river is 90∘+30∘=120∘

A boat crossing a river moves with a velocity v relative to still water. The river is flowing with a velocity $\frac{v}{2}$ with respect to the bank. The angle with respect to the flow direction with which the boat should move to minimize the drift is:

The correct option is D $120^{\circ}$

$θ = s i n^{- 1} (\frac{\frac{v}{2}}{v})$
$θ = 30^{\circ}$
So angle with direction of flow of river is $90^{\circ} + 30^{\circ} = 120^{\circ}$