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Question

A boat going down stream crosses a float at a point A. ′t′1 minutes later the boat reverses its direction and in the next ′t′2 minutes it crosses the float at a distance L from the point A. The velocity of the river is:

A
2Lt1
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B
Lt1+2t2
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C
2L2t1+t2
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D
L2t1
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Solution

The correct option is D L2t1
(D)
Let vb: velocity of boat
vr: velocity of river
In ground frame
for float : L=vr(t1+t2)(1)
for boat : L=(vb+vr)t1(vbvr)t2
L=vr(t1+t2)+vb(t1t2) (2)
solving(1) & (2)
t1=t2
From (1) vr=Lt1+t2

vr=L2t2=L2t1


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