Question

A boat in a circular lakes lies at the center, about $10m$ away from a bridge lying in $40$ m distance across the circular lake. How much distance will boat have to reach to the extreme point of the left side of the bridge?

Answer 1

Say boat is $AC=10m$ away from bridge $AB=40m$ then

Boat have to travel distance $BC$.

Now,

$B{C}^2=A{C}^2+A{B}^2$

$B{C}^2={10}^2+{40}^2$

$B{C}^2=100+1600$

$BC=\sqrt{1700}=41.23m$