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Standard XII

Physics

EMF and EMF Devices

A boat is mov...

Question

A boat is moving due east in a region where the earth's magnetic field is $5.0 \times 10^{- 5} {NA}^{- 1} m^{- 1}$ due north and horizontal. The boat carries a vertical aerial $2 m$ long. If the speed of the boat is $1.50 {ms}^{- 1}$ , the magnitude of the induced $e m f$ in the wire of aerial is. (in $mV$ )

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Solution

Given:
$B_{H} = 5.0 \times 10^{- 5} N/Am, l = 2 m, v = 1.50 m/sec$

Induced emf is given by , $E = B_{H} l v$

Substituting the data gives,

$E = 5 \times 10^{- 5} \times 2 \times 1.50 = 0.15 mV$

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A boat is moving due east in a region where the earth's magnetic field is 5.0×10−5 NA−1m−1 due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms−1, the magnitude of the induced emf in the wire of aerial is. (in mV)

Given: BH=5.0×10−5 N/Am , l=2 m , v=1.50 m/sec Induced emf is given by , E=BHlv Substituting the data gives, E=5×10−5×2×1.50=0.15 mV

Given:
$B_{H} = 5.0 \times 10^{- 5} N/Am, l = 2 m, v = 1.50 m/sec$

Induced emf is given by , $E = B_{H} l v$

Substituting the data gives,

$E = 5 \times 10^{- 5} \times 2 \times 1.50 = 0.15 mV$