A boat of mass 3000kg, initially at rest is pulled by a force of 1.8×104N through a distance of 3m. Assuming that the resistance due to water is negligible, velocity of boat is:
Here, we are given that the boat is initially at rest.
Thus, u=0, mass m=3000kg, distance s=3m.
Substituting, we have
a=F/m=1.8×1043000=6m/s2
But from equation of motion, we have v2−u2=2as.
Substituting the values,
v2−0=2×6×3=36
v=6m/sec.
Thus, the velocity of the boat is 6m/sec.