Let the men
P,Q,R,S,T,U,V,W and suppose
P,Q,R remain only on one side and
S,T on the other as represented in the first figure.
Then, since
4 men must row on each side, of the remaining
3, one must be placed on the side of
P,Q,R and the other two on the side of
S,T; this can evidently be done in
3 ways, for we can place any one of the three on the side of
P,Q,R.
Now
3 ways of distributing the crew let us first consider one, way, say that in which
U is on the side of
P,Q,R as shown in the second figure.
Now
P,Q,R,U can be arranged in
4 ways and
S,T,V,W can be arranged in
4! ways. Hence total no. pf ways arranging the men
=4!×4!=576Hence the number of ways of arranging the crew
=3×576=1728∴K=12