A bob of mass 500g attached to a light inextensible string revolving vertically in a radius R is given an initial velocity v=√7gR at the bottom most point. The tension in the string at the bottom most point is
A
40N
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B
35N
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C
5N
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D
20N
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Solution
The correct option is A40N At the bottom most point, let the tension be T is upwards & weight of bob is downwards
∴ By the FBD of the bob at the bottom most point, we get
T−mg=mv2R ⇒T=mg+mv2R
=mg+m(√7gR)2R=8mg
Where the mass m of the bob is given as 500g=0.5kg