A bob of mass ′m′ is attached to ceiling of a lift with the help of string as shown. Calculate tension in string when lift is accelerated up with acceleration ′a′.
A
m(g+a)
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B
m(g−a)
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C
m√g2+a2
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D
mg
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Solution
The correct option is Am(g+a) as acceleration is up,
In frame of reference of lift pseudo force acts downward . So, FBD is
where ma is the pseudo force acting on the bob of mass m which is creating tention in the string ⇒T=m(g+a)