A bob of mass m is suspended by a massless string of length I. The horizontal velocity v at position A is just sufficient to make it reach the point B. The angle θ at which the speed of the bob is half of that at A, satisfies
A
θ=π4
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B
π4<θ<π2
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C
π2<θ<3π4
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D
3π4<θ<π
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Solution
The correct option is D3π4<θ<π v2−u2=2as 52gl−5gl=2(−g)l(1−cosθ)