wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bobbin is pushed along on a rough stationary horizontal surface as shown in the figure. The board is kept horizontal and there is no slipping at any contact points. Find the distance moved by the board when distance moved by the axis of the bobbin is ℓ.


A

ℓR

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

ℓr

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C


VB=ωr+VCM

Let time taken be t, then

=VCM×t

t=lVCM

Distance moved by board

d=VB×t

=(ωr+VCM)lVCM

VCM=ωR

d=(ωr+ωR)lωR

l=(r+RR)

l=(1+rR)


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rolling
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon