Question

A body 8s dropped from height H. The time taken to cover second half of the journey is? ( in terms of H)

Answer 1

If it takes time “T” to reach the ground then,
H = 0.5gT²
T = √(2H/g)

If it takes time “t” to travel first half of the journey then,
0.5H = 0.5gt²
H = gt²
t = √(H/g)

Time taken to cover second half of the journey is = T - t
= √(2H/g) - √(H/g)
= √(H/g)×(√(2) - 1)

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