1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body A is thrown up vertically from the ground with velocity vo and another body B is simultaneously dropped from a height H. They meet at a height H2 if vo is equal to

A
2gH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
gH
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12gH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2gH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B √gHtime taken by first body to reach H2 is t& time taken by second body to fall aheight H2 is t1 then both time should be equal so that both reach the height H2 simultaneouslyFor second body h=12gt2gives H2=12gt21⇒t21=HgFor first body h=ut−12gt2gives H2=v0t−12gt2put t=t1 we get H2=V0√Hg−12.g.H2⇒H2=v0√H9−H2⇒H=v0√H9⇒v0=√gH

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Moment of Inertia of Solid Bodies
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program