A body A moves with uniform acceleration and zero initial velocity. Another body B starts from same point in same direction with constant velocity v. The two bodies meet after time T. The value of T is?

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$D i s \tan c e t r a v e l l e d b y t h e f i r s t b o d y i n t i m e T i s g i v e n b y : s = u t + \frac{1}{2} a t^{2} u = 0 s = \frac{1}{2} a T^{2} w h e r e a i s t h e u n i f o m r a c c e l e r a t i o n . d i s \tan c e t r a v e l l e d b y t h e s e c o n d b o d y i s s a m e w h i c h i s g i v e n b y : s = v T t h e r e f o r e v T = \frac{1}{2} a T^{2} T = \frac{2 V}{a}$

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A body A moves with uniform acceleration and zero initial velocity. Another body B starts from same point in same direction with constant velocity v. The two bodies meet after time T. The value of T is?

Distance travelled by the first body in time T is given by:s = ut +12at2u = 0s = 12aT2where a is the unifomr acceleration.distance travelled by the second body is same which is given by:s = vTthereforevT = 12aT2T = 2Va