A body A starts from rest with an acceleration a1 . After 2 seconds, another body B starts from rest with an acceleration a2 . If they travel equal distances in the 5thsecond after the start of A, then the ratio a1:a2 is equal to
A
5:9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5:7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9:5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9:7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A5:9 According to problem Distance travelled by body A in 5thsec and distance travelled by body B in 3rdsec. of its motion are equal. As we know that the distance travelled by the particle in nth sec is given as Sn=u+a2(2n−1) Thus, we have S5th=S3rd ⇒0+a12(2×5−1)=0+a22(2×3−1) 9a1=5a2⇒a1a2=59