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Standard IX

Physics

Kinetic Energy

A body 'A' tr...

Question

A body 'A' transferred 10 J of heat energy to a body 'B', which got completely converted to the kinetic energy and 'B' started moving with a velocity, v. What is the value of v? (mass of A: 100 g, the mass of B = 200 g)

10 m/s

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14.1 m/s

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20 m/s

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None of the above

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Solution

The correct option is A
10 m/s

Heat transferred from 'A' to 'B' is converted to K.E.

Given $m a s s o f A = 100 g, m a s s o f B = 200 g$

Heat transfered = $10 J$

So, $10 = \frac{1}{2} m v^{2},$

$v^{2} = \frac{10 \times 2}{0.2}$

$v = 10 m / s$

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A body 'A' transferred 10 J of heat energy to a body 'B', which got completely converted to the kinetic energy and 'B' started moving with a velocity, v. What is the value of v? (mass of A: 100 g, the mass of B = 200 g)

The correct option is A 10 m/s Heat transferred from 'A' to 'B' is converted to K.E. Given mass of A=100 g,mass of B=200 g Heat transfered = 10 J So, 10=12mv2, v2=10×20.2 v = 10 m/s

The correct option is A
10 m/s

Heat transferred from 'A' to 'B' is converted to K.E.

Given $m a s s o f A = 100 g, m a s s o f B = 200 g$

Heat transfered = $10 J$

So, $10 = \frac{1}{2} m v^{2},$

$v^{2} = \frac{10 \times 2}{0.2}$

$v = 10 m / s$