A body- acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60- with the force- The work done by the force beA- 200 JB- 100 JC- 300 JD- 250 J

A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of $60^{o}$ with the force, and (iii) normal to the force.(g=10 N $k g^{- 1}$ ).

A body when acted upon by a force of 10kgf gets displaced by 0.5m calculate the work done by the force when the displacement is in the direction of force

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A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60∘ with the force. The work done by the force be

The correct option is D 250 JW=→F.→S=FScosθ =50×10×cos60∘=50×10×12 =250 J

A body, acted upon by a force of $50 N$ is displaced through a distance $10$ meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

The correct option is D $250 J$
$W = \to F . \to S = F S cos θ$
$= 50 \times 10 \times cos 60^{\circ} = 50 \times 10 \times \frac{1}{2}$
$= 250 J$