A body- acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60- with the force- The work done by the force beA- 200 JB- 100 JC- 300 JD- 250 J

The correct option is D 250 JW = nbsp;F. nbsp;S = FS cosθ nbsp;= 50 × 10 ×cos 60^∘ = 50 × 10 ×12 = 250 J nbsp; ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

A body, acted...

Question

A body, acted upon by a force of $50 N$ is displaced through a distance $10$ meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

200 J

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100 J

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300 J

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250 J

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Solution

The correct option is D $250 J$
$W = \to F . \to S = F S cos θ$
$= 50 \times 10 \times cos 60^{\circ} = 50 \times 10 \times \frac{1}{2}$
$= 250 J$

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A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60∘ with the force. The work done by the force be

The correct option is D 250 JW=→F.→S=FScosθ =50×10×cos60∘=50×10×12 =250 J

A body, acted upon by a force of $50 N$ is displaced through a distance $10$ meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

The correct option is D $250 J$
$W = \to F . \to S = F S cos θ$
$= 50 \times 10 \times cos 60^{\circ} = 50 \times 10 \times \frac{1}{2}$
$= 250 J$