A body- acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60- with the force- The work done by the force beA- 250 JB- 200 JC- 100 JD- 300 J

The correct option is A 250 J W=F⃗.S⃗=FS cos θ=50 × 10 × cos 60^∘=50 × 10 ×1/2=250 J ...

You visited us 81 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Zero Work

A body, acted...

Question

A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

200 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
250 J

$W = \to F . \to S = F S c o s θ = 50 \times 10 \times c o s 60^{\circ} = 50 \times 10 \times \frac{1}{2} = 250 J$

Suggest Corrections

Similar questions

Q. A body, acted upon by a force of

50 N

is displaced through a distance

10

meter in a direction making an angle of

60^{\circ}

with the force. The work done by the force be

Q. A body acted upon by a force of

50 N

is displaced through a distance

10 m

in a direction making an angle of

60^{\circ}

with the force. The work done by the force is
(Take

W = \to F . \to S

, where

W

is work done,

\to F

is force and

\to S

is the displacement)

Q. A body acted upon by a force of

50 N

is displaced through a distance

10 m

in a direction making an angle of

60^{\circ}

with the force. The work done by the force is
(Take

W = \to F . \to S

, where

W

is work done,

\to F

is force and

\to S

is the displacement)

A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of $60^{o}$ with the force, and (iii) normal to the force.(g=10 N $k g^{- 1}$ ).

A body when acted upon by a force of 10kgf gets displaced by 0.5m calculate the work done by the force when the displacement is in the direction of force

Join BYJU'S Learning Program

A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60∘ with the force. The work done by the force be

The correct option is D 250 J W=→F.→S=FS cosθ=50×10×cos 60∘=50×10×12=250 J

A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

The correct option is D
250 J

$W = \to F . \to S = F S c o s θ = 50 \times 10 \times c o s 60^{\circ} = 50 \times 10 \times \frac{1}{2} = 250 J$