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Question

A body at 110°C is dropped into water at 100°C. What happens to the quantity of water in the container?


A

remains the same

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B

increases

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C

decreases

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D

the body converts to the liquid state

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Solution

The correct option is C

decreases


The explanation for the Correct Option:

Option C

  1. It is given that water is at 100°C. And the body is at 110°C which is dropped.
  2. We know that the boiling point of water is 100°C
  3. And, heat flows from the body at higher temperatures to the body at a lower temperature
  4. When a body is dropped into water, it will suddenly transfer the heat to the water, which will ultimately increase the temperature of water above 100°C
  5. And, we know when it happens, Vaporization will occur. Therefore, the quantity of water will decrease as water will change its state to gas.

The explanation for Incorrect Options:

Option A

  1. This could be correct if the temperature of the object would be less than that of the temperature of the water.
  2. But, this would be incorrect in this case, as the temperature of the object is higher than that of water and evaporation will occur due to the transfer of heat into the water.

Option B

  1. It won't be possible, as the quantity of water could never increase if we drop anything into water except water or ice (and let it melt).

Option D

  1. There is no possibility for any object to convert to liquid state after being in contact with water at 100°C
  2. As the object is at a higher temperature, it may be in molten form, which can be converted to solid-state, but vice-versa is not possible.

Hence option C is correct.


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