A body at rest starts sliding from top of a smooth inclined plane and requires 4s to reach bottom. How much time does it take, starting from rest at top, to cover one-fourth of a distance?
A
1s
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B
2s
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C
3s
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D
4s
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Solution
The correct option is D2s Body at rest starts sliding down. Given: t=4s Here, u=0⇒a=gsinθ Distance covered, s=0×4+12(gsinθ)(4)2 ......(i)
In second case: Body rolls up from rest. Hence, u=0⇒a=−gsinθ Here, distance covered s4=0×t−12(gsinθ)(t2) .....(ii)
Dividing equation (i) and (ii), we get: ss4=12(gsinθ)(4)2−12(gsinθ)(t)2⇒t=2s