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Question

A body at rest starts sliding from top of a smooth inclined plane and requires 4s to reach bottom. How much time does it take, starting from rest at top, to cover one-fourth of a distance?

A
1s
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B
2s
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C
3s
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D
4s
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Solution

The correct option is D 2s
Body at rest starts sliding down.
Given: t=4 s
Here, u=0a=gsinθ
Distance covered, s=0×4+12(gsinθ)(4)2 ......(i)

In second case:
Body rolls up from rest.
Hence, u=0a=gsinθ
Here, distance covered
s4=0×t12(gsinθ)(t2) .....(ii)

Dividing equation (i) and (ii), we get:
ss4=12(gsinθ)(4)212(gsinθ)(t)2t=2s

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