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Question
A body cools from 80∘C to 50∘C in 5 minutes. Calculate the time it takes to cool from 60∘C to 30∘C. The temperature of the surrounding is 20∘C.
A body cools from 80∘C to 50∘C in 5 minutes. Calculate the time it takes to cool from 60∘C to 30∘C. The temperature of the surrounding is 20∘C.
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Solution
The correct option is D 10 min
In(T1−T0T2−T0)=kt
In(80−2050−20)=5k ....(i)
In second case In (60−2030−20)=kt′ .....(ii)
From (i) and (ii)
In 4In 2=kt′5k=t′5
In 22In 2=t′5
t′=10 min
10 min
In(T1−T0T2−T0)=kt
In(80−2050−20)=5k ....(i)
In second case In (60−2030−20)=kt′ .....(ii)
From (i) and (ii)
In 4In 2=kt′5k=t′5
In 22In 2=t′5
t′=10 min
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