A body describing circular path at uniform speed of 2m/s takes 33 second to complete 3.5 revolution. The radius of the circular path is what?

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Solution

$T o t a l d i s \tan c e c o v e r e d = 2 \times 33 = 66 m N o w, D i s \tan c e c o v e r e d i n o n e r o t a t i o n = \frac{66}{3.5} = 18.86 m N o w, d i s \tan c e c o v e r e d i n o n e r o t a t i o n w i l l b e t h e c i r c u m f e r e n c e o f t h e p a t h w h i c h m e a n s 2 π R = 18.86 m R = \frac{18.86}{2 π} = 3.003 m$

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A body describing circular path at uniform speed of 2m/s takes 33 second to complete 3.5 revolution. The radius of the circular path is what?

Total distance covered = 2×33 = 66 mNow, Distance covered in one rotation = 663.5 = 18.86 mNow, distance covered in one rotation will be the circumference of the pathwhich means2πR = 18.86mR = 18.862π = 3.003 m