CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A body dropped from the top of a tower covers a distance 7x in the last second of its journey where x is the distance covered in first second. How much time does it take to reach the ground (Take g=10 m/s2)?

A
3 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4 s
In first second, distance travelled x=12×g×t2=5 m
(for g=10 m/s2)
Distance travelled in last second =7x=35 m
We know that Sn=u+12a(2n1)
or 35=0+102×(2n1)
n=4
t=4 s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Free Fall
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon