A body dropped from the top of a tower covers a distance 7x in the last second of its journey where x is the distance covered in first second. How much time does it take to reach the ground (Take g=10m/s2)?
A
3s
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B
4s
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C
5s
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D
6s
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Solution
The correct option is B4s In first second, distance travelled x=12×g×t2=5m
(for g=10m/s2)
Distance travelled in last second =7x=35m
We know that Sn=u+12a(2n−1)
or 35=0+102×(2n−1) ⇒n=4 ∴t=4s