A body dropped from the top of a tower reaches the ground in $4 s$ . Height of the tower is (Take $g = 9.8 m / s^{2}$ ):

39.2 m

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44.1 m

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58.8 m

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78.4 m

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Solution

The correct option is C $78.4 m$
We have, $s = u t + \frac{1}{2} a t^{2}$
Given,
$t = 4 s e c$
$a = g$
$u = 0$
$\Rightarrow s = \frac{1}{2} g t^{2}$
$s = \frac{1}{2} g (4)^{2} = 8 g = 8 \times 9.8 = 78.4 m$
Height of the tower = 78.4 m

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