1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body executes SHM under the influence to one force and has time period ′T′1 seconds and the same body executes SHM with period ′T′2 seconds when under the influence of another force. When both forces act simultaneously and in the same direction then the time period of the same body is?

A
(T1+T2)sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
T21+T22sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
T1+T2T1T2sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
 T21T22(T21+T22)sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D  ⎷T21T22(T21+T22)secUnder the forceF1 time oscillation of the body T1F1=M(2πT1)2V;whereMisthemassandvisthevelocityandF2=M(2πT2)2VFNet=F1+F2M(2πT)2=M(2πT1)2+M(2πT2)21T2=1T21+1T22=T21+T22T21T22=T1T2√T21+T22

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Momentum Returns
PHYSICS
Watch in App
Join BYJU'S Learning Program