A body executing SHM has a total energy E. When its kinetic energy is 3E4 , the displacement of the particle is ( a is amplitude ):
K=E−U=3E4
⇒U=E4=14(12Ka2)=12K(a2)2∴x=a2
A particle starts executing S.H.M. of amplitude a and total energy E. At the instant its kinetic energy is 3E4 , its displacement y is given by