Question

A body executing simple harmonic motion has a maximum acceleration equal to 24 metres/$se{c}^2$ and maximum velocity equal to 16 meters/sec. The amplitude of the simple harmonic motion is

[MP PMT 1995; DPMT 2002; RPET 2003; Pb. PET 2004]

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Maximum velocity = $a\omega$ = 16

Maximum acceleration = ${\omega }^{2}a$ = 24

$\Rightarrow a=\frac{(a\omega {)}^2}{{\omega }^{2}a}=\frac{16\times 16}{24}=\frac{32}{3}m$