Question

A body falling for 2 s, covers a distance equal to that covered in the next second :

• A. 30 m
• B. 10 m
• C. 60 m
• D. 20 m

Answer 1

The correct option is A 30 m

The distance cover in 2s is $S=ut+\frac{1}{2}g{t}^2=u\left(2\right)+0.5\left(g\right)(2{)}^2=2u+2g$ ..(1)

and the distance in traveled in next second is $S=u+g/2(2n-1)=u+g/2(2\times 3-1)=u+5g/2$ ...(2)

Now, $2u+2g=u+5g/2$ or $u=g/2$

Now putting the value of $u$ in (1), $S=2\left(g/2\right)+2g=3g=3\left(10\right)=30m$