Question

A body falling for 2 seconds covers a distance S equal to that covered in next second. Taking g=10m/$s^2$,S =

• A. 30 m
• B. 10 m
• C. 60 m
• D. 20 m

Answer 1

The correct option is A 30 m

If u is the initial velocity then distance covered by it in 2 sec
S=ut+$\frac{1}{2}a{t}^2=u\times 2+\frac{1}{2}\times 10\times$4=2u+20 ...(i)
Now distance covered by it in $3^{rd}$ sec
$S_{3^{rd}}=u+\frac{g}{2}(2\times$3-1)=u+25 ...(ii)
From (i) and (ii), 2u+20=u+25$\Rightarrow$ u=5
$\therefore$ S=2$\times$5+20=30 m