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Question

A body falling from a height of 10 m rebounds from hard floor. If it loses 20 energy in the impact, then coefficient of restitution is .....

A
0.89
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B
0.56
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C
0.23
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D
0.18
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Solution

The correct option is A 0.89
KE just before the collision will be loss in PE so Ki=mgh=m×10×10=100m
loss due to impact was 20 % so remaining KE will be Kf=100m×80% or Kf=100m×0.8=80m
Now the velocity of strike will be Vi=2Kim=102m/s
and the velocity after rebound will be Vf=2Kfm=410m/s
coeefificient of restitution will be e=VfVi=410102=0.89

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